Answer by Thomas Browning for Classify the groups of order $88$ up to...
You're going to need to use Sylow's theorems.If $n_{11}$ is the number of Sylow $11$-subgroups of $G$ then $n_{11}\bigm|88$ and $n_{11}\equiv1\pmod{11}$ so $n_{11}=1$.Then $G$ has a normal Sylow...
View ArticleClassify the groups of order $88$ up to isomorphism.
Classify the groups of order $88$ up to isomorphism.Here is what I have so far (I'm aware that there are $12$ groups, but I don't know which ones I'm missing as well as why the $3$ groups are abelian...
View Article
More Pages to Explore .....
